Question

A car has a velocity of 8 ms^-1. It accelerates uniformly at 2 ms^-2 for 5 s. What will be the final velocity? ​

Answer 1

Given :

• Initial velocity (u) = 8 m/s
• Acceleration (a) = 2 m/s²
• Time (t) = 5 seconds

To find :

• Final velocity (v)

According to the question,

→ v = u + at

Where,

• v stands for Final velocity
• u stand for Initial velocity
• t stands for Time
• a stands for Acceleration

→ Substituting the values,

→ v = 8 + 2 × 5

→ v = 8 + 10

→ v = 18

.°. The final velocity is 18 m/s...

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More formula :-

Newton's first equation of motion :

• v = u + at

Newton's second equation of motion :

• s = ut + ½ at²

Newton's third equation of motion :

• v² = u² + 2as

Answer 2

Given :-

• Initial Velocity (u) = m/s
• Acceleration (a) = 2m/s^2
• Time = 4 seconds

To find :-

• Velocity

According to the question,

➡v = u +at

where,

• v stands for final velocity
• u stands for initial velocity
• t stands for time
• a stands for acceleration

➡ Substituting the values

➡ v = 8 + 2 × 5

➡ v = 8 + 10

➡ v = 18

Therefore, the final velocity is 18 m/s

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More Formula :-

Newton's First Equation Of Motion :

• v = u + at

Newton's Second Equation Of motion :

• s = ut + 1/2 at^2

Newton's Third Equation Of Motion :

• v^2 = u^2 + 2as

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