Question

a car has an acceleration of 8 m/s2.
a. how much time is needed for it to reach a velocity of 24 m/s if it starts from rest?
b. how far does it go during this period?

Answer 1

acc. is 8m/s2
initial velocity(u)=0m/s
final velocity(v)=24m/s2
time (t)=?
as v=u+at
therefore, t=(v-u)/t
={(24-0)/8}sec
=(24/8)sec
=3sec.
as distance is s×t
therefore, distance is 24×3
=72m.
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Answer 2

The time taken by car is 3s. During this period, the car traveled a displacement of 36m.

Step-by-step Explanation:

Given: Acceleration 'a' = 8 m/s²

Final Velocity 'v' = 24 m/s

Initial Velocity 'u' = 0 m/s

To Find: Time taken and Displacement

Solution:

• Time taken by the car

The first equation of motion 'v = u + at' can be used to determine the time 't' taken by the car. Therefore, substituting the given values to get;

⇒ 24 = 0 + 8t

⇒ t = 24/8 = 3s

⇒t = 3s

• Displacement of the car

And, using the third equation of motion, 2as = v² - u², we can find the displacement 's'. Therefore,

⇒ 2 × 8 ×s = (24)² - (0)²

⇒ s = 576/16 = 36m

⇒ s = 36m

Hence, the time taken by car is 3s. During this period, the car traveled a displacement of 36m.