Question

A car has an initial velocity of 20m/s and acceleration of 4 ms .find the distance travelled after 10 sec

Answer 1

Given,
initial velocity,u=20 m/s
time,t=10 s
acceleration,a=4ms^-2
s=ut+1/2at²
s=20×10+1/2×4×10×10
s=200+200
s=400 m
Therefore distance traveled after 10 s is 400m.