Question

A car has an initial velocity of 7.0 m/s. If it accelerates at a constant rate of 2.0 m/s² for a period of 5s, what is its velocity at the end of 5 seconds?​

Answer 1

Answer:

17 m/s

Explanation:

As per the provided information in the given question, we have :

• Initial velocity (u) = 7.0 or 7 m/s
• Acceleration (a) = 2.0 or 2 m/s²
• Time taken (t) = 5 seconds

We are asked to calculate its velocity at the end of 5 seconds i.e, its final velocity.

By using the first equation of motion,

⇒ v = u + at

• v denotes final velocity
• u denotes initial velocity
• a denotes acceleration
• t denotes time

⇒ v = 7 + 2(5)

⇒ v = 7 + 10

⇒ v = 17 m/s

∴ Its velocity at the end of 5 seconds is 17 m/s.

Learn More :

$\boxed{ \begin{array}{cc} \pmb{\sf{ \quad \: v = u + at \quad}} \\ \\ \pmb{\sf{ \quad \: s= ut + \cfrac{1}{2}a{t}^{2} \quad \: } } \\ \\ \pmb{\sf{ \quad \: {v}^{2} - {u}^{2} = 2as \quad \:}}\end{array}}$

• v denotes final velocity
• u denotes initial velocity
• a denotes acceleration
• t denotes time
• s denotes distance