Question

a car has initial velocity of 20m/s and is accelerated at 2ms^-2. calculate the distance covered after 3 secs​

Answer 1

Answer:

initial velocity of car = u = 20m/s

accelaration = a = 2m/s²

time = 3 seconds.

using position time relation

S = ut + 1/2(at²)

S = 20 × 3 + (2 × 3²)/2

S = 60 + 3²

S = 60 + 9

S = 69 m

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Answer 2

Answer:

Distance travelled = 69m

Explanation:

Here initial velocity (u)= 20m/s

Acceleration = 2m/s²

Time= 3s

According to 1st equation of motion,

v=u + at

v= 20+2×3

v== 26m/s.

Now according to third eqation of motion,

v²-u²= 2as

(26)²-(20)²= 2×2×s

676-400= 4s

276/4=s

69=s.