Question

a car has initial velocity of 72 kilometre per hour is it is accelerated at 2 metre per second calculate the final velocity and the distance covered after 3 second

Answer 1

Answer:

Distance is 69m

Final velocity is 26m/s

Explanation:

Initial velocity (u) =72km/hr=(72 × 1000/3600)m/s =20m/s

Acceleration (a) =2m/s^2

Time (t) =3s

Lets distance be 's'

s=ut +1/2at^2

s=20(3) + 1/2 × 2 × 3^2

s=60 + 1/2 × 2 ×9

s=60 + 9

s=69m

Let the final velocity be 'v'

v=u+at

v=20 + 2(3)

v=20 + 6

v=26m/s