Question

A car has initial velocity of 72km h-1. If is accelerated at 2ms-2calculated the final velocity and distance covered after 3 sec.

Answer 1

Explanation:

Here,

Initial velocity (u) = 72 × 5. = 20 m/s

18.

Acceleration (a)= 2 ms -2

Time ( t)= 3 secs.

A/ Q

v = u + àt

=. v = 20 m/s + ( 2× 3 )

= v = 20 + 6

v = 26 m/s

Hence, final velocity is 26 m/s.

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