Question

A car has two wipers which do not overlap. Each
wiper has a blade of length 25 cm sweeping through
an angle of 115º. Find the total area cleaned at each
sweep of the blades.​

Answer 1

Answer:

1254.96cm²

Step-by-step explanation:

Given:

>> length of blade = 25cm

>> Angle sweeping through = 115°

To Find :-

>> Total Find the total area cleaned at each

>> Total Find the total area cleaned at eachsweep of the blades =?

Formula used:-

${\bf {\boxed{\bf{\dfrac{Angle \ of \ sector}{360} \times \pi r^2 sq. units.}}}}$

Procedure:-

Let's start by finding the area swept by one blade, which would be the area of sector.

We know formula :-

${\bf {\boxed{\bf{\dfrac{Angle \ of \ sector}{360} \times \pi r^2 sq. units.}}}}$

Putting the known values in:-

${\bf \implies {{\bf{\dfrac{115cm}{360} \times \dfrac{22}{7} 25^2 sq. units.}}}}$

${\bf \implies {{\bf{\dfrac{158125}{2520}}}}}$

=> Area swept by one blade = 627.480cm²

Area cleaned by two blades :-

$\bf \implies 627.480 \times 2$

=> Area cleaned by two blades = 1254.96 cm²

Answer 2

Given,

Radius (r) = 25 cm

Sector angle (θ) = 115°

Since there are two blades,

The total area of the sector made by wiper,

$= 2 \times ( \frac{θ}{360} ) \times \pi {r}^{2}$

$= 2 \times ( \frac{115}{360} ) \times ( \frac{22}{7} ) \times {25}^{2}$

$= 2 \times \frac{158125}{252} \: \: {cm}^{2}$

$= \frac{158125}{126} \: \: {cm}^{2}$

$= 1254.96 \: \: {cm}^{2}$