Question

A car has two wipers which do not overlap. Each wiper has a blade of length 25 cm sweeping through an angle of 115°. Find the total area cleaned at each sweep of the blades.​ ​

Answer 1

Given,

Radius (r) = 25 cm

Sector angle (θ) = 115°

Since there are two blades,

The total area of the sector made by wiper,

$= 2 \times ( \frac{θ}{360} ) \times \pi {r}^{2}$

$= 2 \times ( \frac{115}{360} ) \times ( \frac{22}{7} ) \times {25}^{2}$

$= 2 \times \frac{158125}{252} \: \: {cm}^{2}$

$= \frac{158125}{126} \: \: {cm}^{2}$

$= 1254.96 \: \: {cm}^{2}$

Answer 2

Answer:

Given,

Radius (r) = 25 cm

Sector angle (θ) = 115°

Since there are two blades,

The total area of the sector made by wiper,

= 2 \times ( \frac{θ}{360} ) \times \pi {r}^{2}=2×(

360

θ

)×πr

2

= 2 \times ( \frac{115}{360} ) \times ( \frac{22}{7} ) \times {25}^{2}=2×(

360

115

)×(

7

22

)×25

2

= 2 \times \frac{158125}{252} \: \: {cm}^{2}=2×

252

158125

cm

2

= \frac{158125}{126} \: \: {cm}^{2}=

126

158125

cm

2

= 1254.96 \: \: {cm}^{2}=1254.96cm

2.