Question

م A car has uniform acceleration of 4 m/s² what distance will it cover in 10 Seconds after start.r​

Answer 1

Answer:

The car covers a distance of 200m in 10s with uniform accileration of 4m/s^2

Explanation:

Acceleration (a) = 4m/s^2

Initial velocity (u) = 0m/s

Time (t) = 10s

Final velocity (v) = u + at

v = 0 + 4 * 10

v = 40m/s

Now,

Distance (S) = Avg.velocity * Time (t)

S = (v+u)/2 * t

S = (40+0)/2 * 10

S = 40/2 * 10

S = 20 * 10

S = 200m