a car has uniform acceleration of 8m per second square what is distance covered in 2sec after starting rest?
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acceleration=8m/s*2
time=2s
initial velocity=0m/s (since the car was at rest)
distance=?
using the second equation of motion we have:
s=ut+1/2at^2
s=0×2+1/2(8×2)
s=0+1/2(16)
s=8m
time=2s
initial velocity=0m/s (since the car was at rest)
distance=?
using the second equation of motion we have:
s=ut+1/2at^2
s=0×2+1/2(8×2)
s=0+1/2(16)
s=8m
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