A car having an initial velocity of 12 meters per second east slows uniformly to 2 meters per second east in 4.0 seconds. The acceleration of the car during this 4.0 second interval is
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v₀ = initial velocity of the car in east direction = 12 m/s
v = final velocity of the car in east direction = 2 m/s
t = time interval = 4 sec
a = acceleration of the car
acceleration of the car is given as
a = (v - v₀)/t
inserting the values in the above equation
a = (2 - 12)/4
a = - 2.5 m/s²
hence the acceleration of car is 2.5 m/s² in west direction. the negative sign indicates opposite direction
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Answer: is it 6.0, 2.5
Explanation:
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