a car having initial velocity 15 m/s moves with constant acceleration of 2 m/s÷s on straight road. displacement of car in 5th second of its motion is
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Answer:
Given,
initial velocity(u) =15m/s
acceleration (a) =2m/s²
time (t) =5
A/Q
Newton 2nd eq of motion
S=ut +1/2at²
=15×5+1/2×2×(5)²
=75+25
=100m
dispalcement is 100m
brainer79:
answer is 24 m
check the answer again
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