a car having mass 1200 kg is uniformly accelerated from rest and covered a distance of 40 metre is 4 seconds calculate the work done by the healing and of car during this time what is the kinetic energy of car at last
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initial u =0
s= 40m
t= 4s
using 2nd equation of mition
s=ut+1/2at^2
40=1/2×a×4×4
a=5m/s
using 1st equation of mition
v=u+at
v=5×4
v=20
F= ma
=1200×5
=6000j
W = fs
w = 6000×40
=240000j
K E= 1/2mv^2
=1/2×1200×20×20
=240000j
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