Question

A car headlamp of 48 W works on the car battery of 12 V. The correct fuse for the circuit of this car headlamp will be:
??????????????????????????????????????????????????????????????????????????

Answer 1

$\bigstar$ Given

A car headlamp of 48 W works on the car battery of 12 V

$\bigstar$ To Find

The correct fuse for the circuit of this car headlamp

$\bigstar$ Solution

We know that

$\orange{\rm \longrightarrow P=VI}$

Hence

$\pink{\rm \longrightarrow I=\dfrac{P}{V}}$

We also know that

Fuse is equal to 1.25 times of the normal operating current

$\red{\rm \longrightarrow I=\dfrac{P}{V} \times 1.25 \ A}$

Here

• I = Fuse
• P = Power
• V = Voltage

Units

• I = Ampere (A)
• P = Watt (W)
• V = Volt (V)

According to the question

We are asked to find the correct fuse for the circuit of this car headlamp

Therefore

We must find "I"

Given that

A car headlamp of 48 W works on the car battery of 12 V

Hence

• P = 48 W
• V = 12 V

Substituting the values

We get

$\blue{\rm \longrightarrow I=\dfrac{48}{12} \times 1.25 \ A}$

$\green{\rm \longrightarrow I=4 \times 1.25 \ A}$

Therefore

$\purple{\rm \longrightarrow I=5 \ A}$

Hence

The correct fuse for the circuit of this car headlamp = 5 A

Answer 2

Answer:

QuEsTiOn

A car headlamp of 48 W works on the car battery of 12 V. The correct fuse for the circuit of this car headlamp will be:

To find

$\: fuse \: for \: the \: circuit \: of \: the \: car \: headlamp$

$\star \: answer \star$

We know that

$\small \pink {p = vi}$

Hence

$\small \blue {i \: = \frac{p}{v} }$

$\small \green {I \: = \frac{p}{v} \times 1.25 Ampere}$

$\small \blue {I = \frac {48}{12} \times 1.25 ampere}$

$\small \green{I = 4 \times 1.25 ampere}$

$\huge \pink {correct \: fuse\: for\: the\: circuit \: of this\: car \:headlamp \: will \: be = 5 Ampere}$