Question

A car hire firm has 2 cars which is hired out everyday. The number of demands per dayfor a car follows Poisson distribution with mean 1.20. What is the proportion of days on
which some demand is refused?

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Answer 1

Given :  A car hire firm has 2 cars which is hired out everyday. The number of demands per day for a car follows Poisson distribution with mean 1.20.

To find : What is the proportion of days on  which some demand is refused

Solution:

P(x)  = λˣ  e^(-λ) / x!

Mean demand =   λ = 1.2

Demand is not refused if demand  is 0 , 1 or  2

Demand is refused if more than 2

Demand is not refused = P(0) + P(1) + P(2)

= 1.2⁰ * $e^{-1.2}$ / 0!  + 1.2¹ *

=     0.301  +  0.3614  +  0.2169

= 0.8793  

Demand is refused  1  -  0.8793  =   0.1207

proportion of days on   which some demand is refused    0.1207

0.12  ( approximate)

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Answer 2

Answer:

here's the right ans as follows hope it's useful::::