Physics, asked by vankadabhavana, 4 months ago

a car ia moving with the acceleration 2m/s2 form test find the distance traveled by the car in the 5thsecond​

Answers

Answered by Anonymous
6

\huge{\mathbb{\red{ANSWER:-}}}

Given :-

\sf{For \: a \: car-}

\sf{acceleration(a) = 2 \: m/s^{2}}

\sf{time(t) = 5 \: second}

To Find Out :-

\sf{how \: much \: distance \: covered \: by}

\sf{the \: car ? }

Using Formulas :-

\sf{Second \: eq. \: of \: Newton's \: law:-}

\sf{S = ut + \dfrac{1}{2}at^{2}}

Explanation :-

\sf{During \: rest- \: u = 0 \: m/s^{2}}

\sf{Now-}

\sf{S = 0\times 5 + \dfrac{1}{2}\times 2\times (5)^{2}}

\sf{S = 0 + \dfrac{1}{2}\times 2\times 25}

\sf{S = 0 + 1\times 25}

\sf{S = 0 + 25}

\sf{S = 25 \: meter}

\sf{The \: car \: travelled \: distance \: of \: 25 \: meter}

Extra related formulas :-

1)\sf{v = u + at}

2)\sf{v^{2} = u^{2} + 2as}

3)\sf{a =\dfrac{v - u}{t}}

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