Question

A car in front of the school goes from rest to 27 m/s in 3.0 seconds. What is its acceleration (assuming it is constant)?​

Answer 1

Answer:

initial velocity = 0

final velocity = 27

time required for acceleration = 3.0sec

a = v - u/t

a = 27 - 0/3

a = 9 m/s^2

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Answer 2

Given : Car in front of the school goes from rest to 27 m/s in 3.0 seconds.

To Find : Acceleration of the car.

Solution :

Car in front of the school goes from rest to 27 m/s in 3.0 seconds.

Initial velocity = 0 m/s

Final velocity = 27 m/s

Time travelled = 3.0sec

$\[a = \frac{{v - u}}{t}\]$

$\[a = \frac{{27 - 0}}{3}\]$

$\[a = 9m/{s^2}\]$.

Hence, Acceleration of car is $\[9m/{s^2}\]$.