A car in moving with velocity 60 kmph along northward direction suddenly the driver of the car changes the direction of motion of the car along 30° north of East without changing its speed. Then find magnitude and direction of change in velocity
Answers
Answered by
1
Explanation:
V
b
= velocity of bus
V
c
= velocity of car
V
bc
=25
3
km/hr
now from relative velocity
∣
V
b
∣ =
(25)
2
+(25
3
)
2
= 50km/hr
for direction
tanθ=
25
25
3
=
3
so
′
θ
′
is from east direction
Therefore it will be at 30' east of north
Hence (A) is correct
Similar questions