Question

a car increase its speed from 20km/h to 50km/h in 10s its acceleration is

method: v-u/t

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Answer 1

Given:-

• Initial velocity ,u = 20km/h

• Final velocity ,v = 50km/h

• Time taken ,t = 10s

To Find:-

• Acceleration ,a

Solution:-

Firstly we convert the speed into m/s.

Initial velocity = 20×5/18 = 100/18 = 5.55 m/s

Final velocity ,v = 50 ×5/18 = 250/18 = 13.88 m/s

As we know that acceleration is defined as the rate of change of velocity at per unit time.

• a = v-u/t

Where,

a is the acceleration

v is the final velocity

u is the initial velocity

t is the time taken

Substitute the value we get

→ a = 13.88-5.55/10

→ a = 8.33/10

→ a = 0.83 m/s²

Therefore,the acceleration of the car is 0.83 m/s².

Answer 2

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• Intial velocity = u = 20km /hr =20 x 5/18= 5.56m/s.
• Final velocity= v = 50km /hr =50 x 5/18=13.89 m/s.

➺Time = T = 10 second

➺Accerlation= A

⠀

A = (v-u) / t

⠀⠀ =(13.89 - 5.56) / 10

⠀⠀= 0.833 m/s².