a car increase its velocity from 18 km/hr to 36 km/hr in 5 sec at a constant acceleration .fid acceleration and distance covered by it ?
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we know that v = u + at
v= 36
u = 18
t = 5
36 = 18 + 5a
18 = 5a
a = 18/5 m/s^2
s= ut + (1/2)at^2
s = (18)(5) + (1/2)(18/5)(5)(5)
s = 90 + 45
s = 135 m
v= 36
u = 18
t = 5
36 = 18 + 5a
18 = 5a
a = 18/5 m/s^2
s= ut + (1/2)at^2
s = (18)(5) + (1/2)(18/5)(5)(5)
s = 90 + 45
s = 135 m
arunkewat:
bt their unit are different ..km/h,&sec
bt their units are different ..km/h,&sec
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