Question

A car increases its speed by 25 % after that it increases its speed by 20% by what % is the cars final speed greaer than oits orginal speed

Answer 1

Answer:

Let the original speed be x

Find the speed of the car after it increases by 25%:

25% increase = 0.25x

Speed after increase = x + 0.25x = 1.25x

Find the speed of the car after it increases by 20% again:

20% increase = 0.20(1.25x) = 0.25x

Speed after increase = 1.25x + 0.25x = 1.5x

Find the increase:

Increase = 1.5x - x = 0.5x

Find the percentage increase:

percentage increase = (0.5x/x) x 100 = 50%

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Explanation:

Answer 2

Answer:

50%

Explanation:

Let the old new of speed be 100.

Apply the concept of multiplication factor-

( ( (100+p)/100) ( (100+q) / 100) ) will give the value which would be multiplied by the old value to get the new value.

Here,

p = 25

q = 20

So, applying concept of multiplication factor, we get-

((100+20)/100)((100+25)/100) = 1.5

Now, multiply it by old speed (100) to get new speed.

New speed = 100 * 1.5 = 150

Now, increment of speed = 150 - 100 =50

The percentage increment ,

(50/100)*100 = 50%