A car increases its speed from 20 km/h to 50 km/ h in 10 seconds its acceleration is
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Answered by
335
acceleration is change in velocity per unit time
a = (v2-v1)/(t2-t1)
v2-v1 = 30 kmph
= 30×5/18 m/s
= 25/3 m/s
t2-t1 = 10s
a= 25/(3×10) = 5/6 m/s^2
a = (v2-v1)/(t2-t1)
v2-v1 = 30 kmph
= 30×5/18 m/s
= 25/3 m/s
t2-t1 = 10s
a= 25/(3×10) = 5/6 m/s^2
Answered by
562
Hi there !!
Initial velocity = u = 20km/hr = 20 x 5/18 = 5.56 m/s
Final velocity = v = 50 km/hr = 50 x 5/18 = 13.89 m/s
Time = t = 10 sec
Acceleration = a
a = (v- u) / t
= (13.89 - 5.56) / 10
= 0.833 m/s²
Initial velocity = u = 20km/hr = 20 x 5/18 = 5.56 m/s
Final velocity = v = 50 km/hr = 50 x 5/18 = 13.89 m/s
Time = t = 10 sec
Acceleration = a
a = (v- u) / t
= (13.89 - 5.56) / 10
= 0.833 m/s²
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