Question

A car increases its speed from
20 m/sec to 30 m/sec in 5 sec.
The acceleration of the car is​

Answer 1

GIVEN :-

• Initial velocity (u) = 20 m/s.
• Final velocity (v) = 30 m/s.
• Time (t) = 5 second.

TO FIND :-

• The Acceleration of car.

SOLUTION :-

☯ Acceleration = Final velocity/Initial velocity

➬ (v - u)/t

➬ (30 - 20)/5

➬ 10/5

➬ 2

➬ 2 m/s².

Hence the acceleration is 2 m/s².

ADDITIONAL INFORMATION :-

☯ VELOCITY

➠ Velocity :- Velocity of an object is defined as the displacement of an object per unit area.

➠ Velocity = Distance travelled/Time taken.

➠ S.I unit of velocity is m/s.

➠ Velocity has vector quantity because It has magnitude and special direction.

☯ ACCELERATION

➠ Acceleration :- Acceleration of an object is defined as rate of change of velocity of the object with time.

➠ Acceleration = (v-u)/t

➠ S.I unit of acceleration is m/s².

➠ Average acceleration = (v2 - v1)/(t2 - t1)

Answer 2

ANSWER✔

$\large\underline\bold{GIVEN,}$

GIVEN :-

$\sf\dashrightarrow INITIAL\:VELOCITY\:(U)= 20 M/S$

$\sf\dashrightarrow FINAL\:VELOCITY=30 M/S$

$\sf\dashrightarrow TIME(T)=5\:SECONDS$

$\large\underline\bold{TO\:FIND,}$

$\sf\large\dashrightarrow acceleration\:of\:the\:car$

✯FORMULA IN USE,

$\sf\large\therefore a= \dfrac{v-u}{t}$

$\sf\implies a= \dfrac{30-20}{5}$

$\sf\implies a= \dfrac{10}{5}$

$\sf\implies a= \cancel \dfrac{10}{5}$

$\sf\implies a=2$

$\large{\boxed{\bf{ acceleration (a)= 2m/s^2}}}$

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✯ADDITIONAL INFORMATION,

• v(velocity of an object )= $\sf \dfrac{distance\:travelled}{time\:taken(t)}$
• S.I. UNIT FOR VELOCITY= M/S
• a(acceleration)= $\sf \dfrac{v-u}{t}$
• average acceleration= $\sf \dfrac{v_2-v_1}{t_2-t_1}$
• S.I. UNIT FOR ACCELERATION= M/S²

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