a car increases its speed from 20km/hr to 50km/hr in 10 sec. what is its acceleration?
joshihimanshu46:
first u have to change the speed in m/s from km/h
thnks
Answers
Answered by
1
first change 10 sec to hr and then change the acceleration to m/sec^2
Answered by
9
Given,
Initial velocity ( u ) = 20 km/h
Final velocity ( v ) = 50 km/h
Time ( t ) = 10 sec = ( 1/360 )h
Acceleration ( a ) = ?
Using 1st equation of Motion,
⇒ v = u + at
⇒ 50 km/h = ( 20 km/h ) + a( 1/360 )h
⇒ [ ( 50 km/h ) - ( 20 km/h ) ] = a( 1/360 )h
⇒30 km/h = ah/360
⇒( 30 km × 360 ) / ( h × h ) = a
⇒10,800 km/h² = a
•°• a = 10,800 km/h²
Method to convert sec in hour.
We know that,
⇒ 3600 sec = 1 h
⇒ 1 sec = ( 1/3600 )h
⇒ 10 sec = ( 10/3600 )h
•°• 10 sec = ( 1/360 )h
Initial velocity ( u ) = 20 km/h
Final velocity ( v ) = 50 km/h
Time ( t ) = 10 sec = ( 1/360 )h
Acceleration ( a ) = ?
Using 1st equation of Motion,
⇒ v = u + at
⇒ 50 km/h = ( 20 km/h ) + a( 1/360 )h
⇒ [ ( 50 km/h ) - ( 20 km/h ) ] = a( 1/360 )h
⇒30 km/h = ah/360
⇒( 30 km × 360 ) / ( h × h ) = a
⇒10,800 km/h² = a
•°• a = 10,800 km/h²
Method to convert sec in hour.
We know that,
⇒ 3600 sec = 1 h
⇒ 1 sec = ( 1/3600 )h
⇒ 10 sec = ( 10/3600 )h
•°• 10 sec = ( 1/360 )h
Ah well. Your answer is approved. It cannot be Moderated without removal of Approval Check. I will have to someone
Oh
I will have to ask someone*
Bhaiya, plz.. remove its approval as it's wrong
I can't do that. I don't have any option for it
Is it right ?
Yes it is correct. You missed to replace 1/6 in the equation of motion with 1/360, but later it is evident that you are using correct value. Overall the final answer is correct :)
I saw it and told to Ma'm also
Well it's okay though :)) The major error is corrected.
Okay
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