A car increases its speed from 39 km/hr to 75 km/hr in 10 seconds. Its acceleration is a) 3 m/s2 b) 0.8 m/s 2 c) 1 m/s2 d) 8 m/s2
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Given :
Initial velocity of the car = 39 km/hr
final velocity of the car = 75km/hr
Time taken = 10 sec
To find :
The acceleration of the car
Solution :
Firstly we have to convert km/hr to m/s
we know that,
» 1km/hr = 5/18km/hr
» 39km/hr = 39 × 5/18 = 10.8 m/s
» 75km/hr = 75 × 5/18 = 20.8 m/s
Accerlation is the rate of change of velocity.
- It is a vector quantity having both magnitude as well as direction.
- SI unit of acceleration is metre per second square.
As we are provided with initial velocity, final velocity and time we can use first equation of kinematics that is,
v = u + at
- v denotes final velocity
- u denotes initial velocity
- a denotes acceleration
- t denotes time taken
by substituting all the given values in the formula,
➝ v = u + at
➝ 20.8 = 10.8 + a(10)
➝ 20.8 - 10.8 = 10a
➝ a = 10/10
➝ a = 1m/s²
Thus, the acceleration of the car is 1m/s².
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