Question

A car increases its speed from 60km/h to 80km/h
in 5 seconds. Find the acceleration of the car.
​

Answer 1

Hey mate here is your answer

Initial velocity=60 kmph=60×5/18=16.67 m/s

Final velocity=80 kmph=80×5/18=22.22 m/s

acceleration=?

we know,

from first Equations of motion,

$v = u + at$

where,

u=initial velocity

v=final velocity

a=acceleration

t=time taken

Let's substitute the values of known parameters,

$= > 22.22 = 16.67 + a \times 5$

$a = \frac{22.22 - 16.67}{5}$

$a = 1.11 \: ms {}^{ - 2}$

Therefore,

acceleration is 1.11 m/s²

Hope it helps

Answer 2

Answer:

1.11 m/$s^{2}$

Explanation:

initial velocity(u) = 60km/h=  16.67 m/s

final velocity(v) = 80 km/h = 22.22m/s

time taken (t) = 5 s

acceleration = ?

we know,

acceleration = (v-u) / t

                      = (22.22 - 16.67) / 5

                       = 1.11

∴ acceleration = 1.11 m/$s^{2}$