Question

A car increases its velocity from 18 km/h to 36 km/h in 5 sec, at a constant acceleration. Find its
acceleration and distance covered by it.
stons at a distance of 10 m​

Answer 1

Answer: Acceleration: 1 $m/s^{2}$

Distance Covered in 5s= 37.5 metres

Explanation:

Convert km/h to m/s by  multiplying speed by 5/18

Apply  v=u+at in order to find acceleration.

Thereafter, apply s=ut+1/2(at²) to find the distance covered.

Answer 2

Answer & Explanation:

Initial velocity = 18 km/h = 5 m/s

Final Velocity = 36 km/h = 10 m/s

Time taken = 5 seconds

Acceleration = Δv/Δt

                     = 10 - 5/ 5-0

Acceleration = 1 m/s²                         (ANS.)

Distance (s) = ut + 1/2 at²                    [2nd equation of motion]

                    = (5×5) + 1/2 × 1 × 5 × 5

                    = 25 + 25/2

Distance (s) = 37.5 m                          (ANS.)

                                                  OR

v² - u² = 2as                                          [3rd equation of motion]

Distance (s) = v² - u²/2a

                    = 10² - 5²/2 × 1

                    = 100 - 25/2

                    = 75/2

 Distance (s)  = 37.5 m                        (ANS.)