Question

A car increases its velocity from 18 km/h to 36 km/h in 5 sec, at a constant acceleration. Find its
acceleration and distance covered by it.​

Answer 1

Answer:

A = V- U / T

36 - 18 / 5

18 / 5

= 3.6

Explanation:

Hope it's a right answer

Answer 2

Answer:

acceleration = 1m/s²

distance = 37.5m

Explanation:

initial velocity = 18km/h = (18×1000)÷(60×60) m/s

initial velocity = 5m/s

final velocity = 36km/h = (36×1000)÷(60×60) m/s

final velocity = 10m/s

time = 5s

using

v = u + at

10 = 5 + a(5)

a(5) = 10-5 = 5

a = 5/5

a = 1 m / s²

using

v²-u² = 2ad

(10)² - (5)² = (2)(1) d

100 - 25 = 2d

2d = 75

d = 75 ÷ 2

d = 37.5 m