A car increases its velocity from 18 km/h to 36 km/h in 5 sec, at a constant acceleration. Find its acceleration and distance covered by it.
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hey mate your answer↓
v=u+at
36=18+5a
a=36-18/5
a=3.6km/hr^2
s=ut+1/2at^2
=18×5+1/2×3.6×5^2
=90+1.8×25
=90+45
=135 km
acceleration= 3.6 km/hr^2
distance=135km
hope that it will be helpful
hope that it will help you
v=u+at
36=18+5a
a=36-18/5
a=3.6km/hr^2
s=ut+1/2at^2
=18×5+1/2×3.6×5^2
=90+1.8×25
=90+45
=135 km
acceleration= 3.6 km/hr^2
distance=135km
hope that it will be helpful
hope that it will help you
piyush6420singla:
Velocity is in km
ur ans is wrong
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