Physics, asked by theman7349, 1 month ago

a car increases its velocity from 18 km/h to 90 km/h in 10 seconds. Its acceleration is

Answers

Answered by NewGeneEinstein
1
  • Initial velocity=u=18km/h
  • Final velocity=v=90km/h
  • Time=t=10s

Convert velocities to m/s

\\ \sf\longmapsto u=18\times \dfrac{5}{18}=5m/s

\\ \sf\longmapsto v=90\times \dfrac{5}{18}

\\ \sf\longmapsto v=25m/s

We know

\boxed{\sf Acceleration=\dfrac{v-u}{t}}

\\ \sf\longmapsto Acceleration=\dfrac{25-5}{10}

\\ \sf\longmapsto Acceleration=\dfrac{20}{10}

\\ \sf\longmapsto Acceleration=2m/s^2

Answered by TrustedAnswerer19
32

Answer:

\large \green {\boxed {\sf acceleration \:  \: a = 2\: m  {s}^{ - 2} }} \:

Explanation :

Given,

 \sf \odot \: initial  \: velocity \:  \:   u = 18 \: km {h}^{ - 1}  \\ \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \sf =  \frac{18 \times 1000}{3600}  \: m {s}^{ - 1}  \\\:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: \sf  = 5 \:  \: m {s}^{ - 1}  </p><p></p><p> \\  \\ \odot \:  \sf  final  \: velocity  \:  \:   v = 90 km {h}^{ - 1}  \\ \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  =  \frac{90 \times 1000}{3600}  \: m {s}^{ - 1} </p><p> \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  = 25 \: m {s}^{ - 1} \\  \\ \sf \:  \odot \:  time \:   t = 10 \:  s\\  \\  </p><p></p><p> \sf \:  \pink{acceleration \:  \:   a = to  \: find }

Formula :

 \large  \pink {\boxed { \sf\: acceleration \:  \: a =  \frac{v - u}{t} }}

Solution :

\large \sf \:  \:  \: a =  \frac{25 - 5 }{10}    \\  \:  \:  \:  \:  \:  \:  \: =  \frac{20}{10} \\  \sf \:  \:  \:  \:  \:  \:  \:  = 2 \: m {s}^{ - 2}  \\  \\ \large \green {\boxed {\sf  \therefore \: acceleration \:  \: a = 2\: m  {s}^{ - 2} }}

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