A car increse its speed from 18km/h to 36km/h in 5seconds. Caluclate acceleration and distance covered
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u = 18km/hr = 5m/s
v = 36km/hr = 10m/s
t = 5s
a = v-u/t
=> 10-5/5
=>5/5
=>1m/s²
s = ut+½at²
s = 5×5 +½×1×5²
s = 25+12.5
s = 37.5
So, the distance covered us 37.5m.
Cheers!
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