Question

A car initially at rest accelerates on a straight road at a rate of 15 metre - square for 10s how far does a car travel during this time give answer​

Answer 1

Answer:

The car starts from rest therefore the initial speed u = 0. Nothing is said about the initial position and we therefore assume it is equal to 0. Hence the position x is given by the equation

x = (1/2) a t 2

where a is the acceleration (=8 m/s2) and t is the period of time between initial and final positions

x = (1/2)8 (10)2 = 400 m

b) The velocity v of the car at the end of the 10 seconds is given by

v = a t = 8 * 10 = 80 m/s

.

Answer 2

Explanation:

s= 1/2× at +utsq.

s= 1/2×15×10+0

s=75m