A car initially at rest attains a speed of 20m/s in 5 sec and moves with the same speed for the next 20 sec . And comes to rest for the next 10sec a. Plot speed time graph b. Find acceleration c. Find retardation d. Total distance covered
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a) In the picture.
b) a=(v-u)/t=20/5=4m/s^2
c) Here retardation is also acceleration. So,
a=(v-u)/t=(0-20)/10=(-2) m/s^2.
Plz mark it as brainliest..
b) a=(v-u)/t=20/5=4m/s^2
c) Here retardation is also acceleration. So,
a=(v-u)/t=(0-20)/10=(-2) m/s^2.
Plz mark it as brainliest..
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