Question

A car initially at rest moves with a constant acceleration along a straight road. After its speed increases to 40 km/h, it moves with a constant speed and finally retards uniformly. The time intervals for 3 parts of the journey are in the ratio 1:3:1. Find the average velocity.​

Answer 1

hey dear hear is your answer

Answer:

32 km p h

Explanation:

In first case v = a t

==> a t = 40 km p h

Now distance covered S1 + S2 + S3

S1 = 1/2 a t^2 and S3 = 1/2 a t^2

But S2 = 3t * 40 = 120 t km

Hence total distance = at^2 + 120 t

Time taken (total) = t + 3t + t = 5 t

Hence average speed = at^2 + 120 t / 5 t

Cancelling t we have at + 120 / 5 = 40 + 120 / 5 = 160/5 = 32 km p h

Answer 2

Explanation:

here the car is moveing with constant velocity for long time avg velocity is equals to it..