A car initially at rest picks up a velocity of 72 km/h is 20 s.if the mass of car is 1000 kg. calculate(1) force developed by its engine,(2) distance covered by the car
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u=0m/s
v=72km/h=72*5/18=20m/s
t=20 sec
m= 1000kg
1) force = ma
= 1000*(v-u)/t
=1000*(20-0)/20
= 1000*1 = 1000N
2) 2as=v2-u2
2*1*s= (20)2 - (0)2
2s. =. 400
s= 200m.
v=72km/h=72*5/18=20m/s
t=20 sec
m= 1000kg
1) force = ma
= 1000*(v-u)/t
=1000*(20-0)/20
= 1000*1 = 1000N
2) 2as=v2-u2
2*1*s= (20)2 - (0)2
2s. =. 400
s= 200m.
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