Physics, asked by pragati7495, 5 months ago

A car, initially at rest, picks up a velocity of 72 km h^{-1} in 1/4 minute. Calculate acceleration and distance covered by the car​

Answers

Answered by ps1666520
2

Answer:

car initially at rest picks up a velocity of 72 km per hour in 20 seconds if ... is 1000 kg find Force developed by its engine and distance covered by car ... Force = mass×acceleration = 1000× 1 = 1000 N.

Answered by SarcasticL0ve
6

GivEn:

  • Initial Velocity of car, u = 0 m/s
  • Final Velocity of car, v = 72 km/h = 20 m/s
  • Time taken, t = 1/4 minute = 15 s

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Need to find:

  • Acceleration and distance covered by car?

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Solution:

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{\underline{\sf{\bigstar\: According\:to\:the\:question\::}}}\\ \\

☯ Using 1st Equation of motion,

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\star\;{\boxed{\sf{\purple{v = u + at}}}}\\ \\

:\implies\sf 20 = 0 + a \times 15\\ \\

:\implies\sf 20 = 15a\\ \\

:\implies\sf a = \cancel{ \dfrac{20}{15}}\\ \\

:\implies{\boxed{\frak{\pink{a = 1.3\;m/s^2}}}}\;\bigstar\\ \\

\therefore\;{\underline{\sf{Hence,\: Acceleration\:is\: \bf{1.3\;m/s^2}.}}}\\ \\

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☯ Now, Using 2nd equation of motion,

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\star\;{\boxed{\sf{\purple{s = ut + \dfrac{1}{2} at^2}}}}\\ \\

:\implies\sf s = 0 \times 15 + \dfrac{1}{2} \times 1.3 \times (15)^2\\ \\

:\implies\sf s = \dfrac{1}{2} \times 1.3 \times 225\\ \\

:\implies{\boxed{\frak{\pink{s = 146.25\;m/s^2}}}}\;\bigstar\\ \\

\therefore\;{\underline{\sf{Hence,\:the\:distance\:travelled\:by\:car\:is\:{\textsf{\textbf{146.25\:m}}}.}}}

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