a car initially at rest, picks up a velocity of 72 kmph over a distance 25 m the acceleration ofa car is ?
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Answer :
›»› The Acceleration of a car = 8 m/s²
Given :
- Initial velocity of car = 0 m/s
- Final velocity of car = 72 km/hr
- Distance travelled by car = 25 m
To Find :
- Acceleration of car = ?
Required Solution :
Here in this question we have to find the Acceleration of car. So, firstly we have to convert the Final velocity of car km/hr to m/s, after that we will find Acceleration of car on the on the basis of conditions given above.
→ Final velocity = 72 km/hr
→ Final velocity = 72 × 5/18
→ Final velocity = 4 × 5
→ Final velocity = 20 m/s
Now, we have Initial velocity, Final velocity and Distance travelled by car.
- Initial velocity of car = 0 m/s
- Final velocity of car = 20 m/s
- Distance travelled by car = 25 m
And we need to find Acceleration of car.
From third equation of motion
║Hence, the Acceleration of car is 8 m/s².║
Additional Information :
★ First equation of motion :
⪼ v = u + at
Where,
- v is the Final velocity in m/s.
- u is the Initial velocity in m/s.
- a is the Acceleration in m/s².
- t is the Time taken in second.
★ Second equation of motion :
⪼ s = ut + ½ at²
Where,
- s is the Distance travelled in m.
- u is the Initial velocity in m/s.
- a is the Acceleration in m/s².
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