Physics, asked by kadalibullamma4832, 8 months ago

a car initially at rest, picks up a velocity of 72 kmph over a distance 25 m the acceleration ofa car is ?​

Answers

Answered by Anonymous
96

 \huge \red{ \tt Solution:-}

\purple{ \sf Given :-}

  •  \green{\sf Initial \: Velocity \:  (u) = 0  \: m/s}
  •  \green{\sf Final \: Velocity \:  (v) = 72 \: km/hr = 20 \: m/s}
  •  \green{\sf Distance \: Covered \:  (s) = 25  \: m}

 \huge \orange{\bf Calculating \: Acceleration}

 \blue{\tt Formula \: Used :-}

  •  \gray{  \underline {\boxed{ { \tt{ v}^{2} -  {u}^{2}  = 2as }}}}

\implies \pink{( \sf {20)}^{2}  - ( {0)}^{2} = 2 \times a \times 25 }

\implies \pink{ \sf 400 - 0 =  50a}

\implies \pink{ \sf  50a = 400}

\implies \pink{ \sf a =   \cancel{\dfrac{400}{50}} }

\implies \pink{ \sf a = 8}

{\green{ \underbrace{\boxed{\underline{\underline{\purple{ \tt \therefore The \: acceleration \: is \: 8 \: m/s^{2} }}}}}}}

Answered by Anonymous
73

Answer :

›»› The Acceleration of a car = 8 m/s²

Given :

  • Initial velocity of car = 0 m/s
  • Final velocity of car = 72 km/hr
  • Distance travelled by car = 25 m

To Find :

  • Acceleration of car = ?

Required Solution :

Here in this question we have to find the Acceleration of car. So, firstly we have to convert the Final velocity of car km/hr to m/s, after that we will find Acceleration of car on the on the basis of conditions given above.

→ Final velocity = 72 km/hr

→ Final velocity = 72 × 5/18

→ Final velocity = 4 × 5

→ Final velocity = 20 m/s

Now, we have Initial velocity, Final velocity and Distance travelled by car.

  • Initial velocity of car = 0 m/s
  • Final velocity of car = 20 m/s
  • Distance travelled by car = 25 m

And we need to find Acceleration of car.

From third equation of motion

\tt{:\implies {v}^{2} = {u}^{2} + 2as}

\tt{:\implies {20}^{2} = {0}^{2} + 2 \times a \times 25}

\tt{:\implies 400 = 0 + 2 \times a \times 25}

\tt{:\implies 400 = 0 + 2a \times 25}

\tt{:\implies 400 = 0 + 50a}

\tt{:\implies 400 = 50a}

\tt{:\implies \dfrac{40\cancel{0}}{5\cancel{0}} = a}

\tt{:\implies \cancel{\dfrac{40}{5}} = a}

\tt{:\implies 8 = a}

\bf{:\implies \underline{\:\: \underline {\red{\: a = 8 \: m/s^2\:}}\:}}

Hence, the Acceleration of car is 8 m/s².

\:

Additional Information :

First equation of motion :

⪼ v = u + at

Where,

  • v is the Final velocity in m/s.
  • u is the Initial velocity in m/s.
  • a is the Acceleration in m/s².
  • t is the Time taken in second.

Second equation of motion :

⪼ s = ut + ½ at²

Where,

  • s is the Distance travelled in m.
  • u is the Initial velocity in m/s.
  • a is the Acceleration in m/s².

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