Question

a car initially at rest, picks up a velocity of 72 kmph over a distance 25 m the acceleration ofa car is ?​

Answer 1

Answer:

8 m/s²

Explanation:

u = 0

v = 72 kmph = 20 mps

s = 25 m

we have v² - u² = 2as

(20)² = 2.a.25

400 = 50 a

a = 400/50

= 8 mps²

PLEASE MARK AS BRAINLIEST

Answer 2

Answer:

u=o

v=72km/hr

distance=25m

so, v=72000/3600

v=20m/s

now

v^2=u^2+2as

20×20= 0 + 2×a×25

400=50a

a=400/50

a=8

$a =8ms {}^{ - 2}$

answer