Question

A car initially at rest picks up a velocity of 72km/h over a distance of 25m.The acceleration of car

Answer 1

Answer:

u=0m/s

v=72Kmh=20m/s

s=25

v^2- u^2 = 2as

a=v^2 -u^2 /2s

a=400-0/ 2×25

a=8m/s^2

Answer 2

Answer:

8 m/s^2

Explanation:

Initial velocity = O m/s

Initial velocity = O m/s Final velocity = 72 km/hr = 20 m/s

Distance cover= 25 m

Initial velocity = O m/s, Final velocity = 72 km/hr = 20 m/s

Distance cover= 25 m

We know u^2= v^2+2as ( here u is initial velocity, v is final velocity,a is acceleration and s is total distance)

Initial velocity = O m/s Final velocity = 72 km/hr = 20 m/s

Distance cover= 25 m

We know,

u^2= v^2+2as ( here u is initial velocity, v is final velocity,a is acceleration and s is total distance)

Now a = (v^2-u^2)/2s = ( 20^2-0)/(2×25) = 400/50 = 8 m/s^2