a car initially at rest, picks up a velocity of 72km/hr in 20 seconds. if the mass of the car is 1000kg find force developed by its engine
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8
Acceleration, a = 72/3.6 * 20 m/s^2 = 1 m/s^2
Therefore, force developed by the engine, F = m*a = (1000*1) = 1000 N
Therefore, force developed by the engine, F = m*a = (1000*1) = 1000 N
Answered by
15
mass of the car is 1000 kg
and acceleration of the car is 72km/hr for 20 second.
for converting m/s
1km/hr = 5 m/s
18
72* 5 = 20 m/s
18
20m/s in 20 second
so acceleration = 20 m/s = 1 m/s^2
20 s
force F = ma
m= 1000kg
a = 1 m/s^2
⇒ F = ma
⇒ = 1000 * 1
⇒ F = 1000 N
and acceleration of the car is 72km/hr for 20 second.
for converting m/s
1km/hr = 5 m/s
18
72* 5 = 20 m/s
18
20m/s in 20 second
so acceleration = 20 m/s = 1 m/s^2
20 s
force F = ma
m= 1000kg
a = 1 m/s^2
⇒ F = ma
⇒ = 1000 * 1
⇒ F = 1000 N
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