a car initially at rest picks up a velocity of 90km/h in 40 seconds.if the mass of the car is 1500kg.Find the force developed by its engine.
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Answer:
The required force is 937.5 N
Explanation:
Initial velocity, u = 0 m/s
Final velocity, v = 90 km/h
v = 90 × 5/18 m/s
v = 25 m/s
time taken, t = 40 s
mass of the car, m = 1500 kg
First, let's find the acceleration.
Acceleration is the rate of change of velocity.
a = (v – u)/t
a = (25 – 0)/40
a = 25/40
a = 5/8 m/s²
We know that,
F = ma
where
m denotes mass
a denotes acceleration
Substituting the values,
F = 1500 × 5/8
F = 937.5 N
Therefore, the force developed by its engine is 937.5 N
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