Question

A car initially at rest starts moving with a acceleration of 4 m/s.The distance travelled in which it picks up a velocity 72 km/h is​

Answer 1

Answer:

v = u + at

72 = 0 + 4t

t = 72/4

t = 18 sec

now we hv to find distance ,

s = 1/2 at^2

s = 1/2 * 4 * 18*18

s = 648m

good day

Answer 2

Answer:

Here,

a=4m/s, velocity = 72,

v=u+at .....

72=0+4t

72=4t

72/4=t

18=t

t=18 sec

now distance

s=1/2att

s=1/2*4/18*18

s= 648m