Question

A car initially at rest starts moving with a constant acceleration of o.5 m/s^2 and travels a distance of 25m .calculate it's final velocity.

Answer 1

Answer = 5m/s

Given:-

Initial velocity of car(u) = 0

Acceleration = 0.5m/s²

Distance travelled = 25m

To find :-

Final velocity of car (v)

Solution:-

When acceleration is constant we can use equation of motion.

$\boxed{\sf{ 2as = V^2 - U^2}}$

As, U = 0

then,

$\implies$ $2 × 0.5 × 25 = {v}^2$

$\implies$ $25 = {v}^2$

$\implies$ $v = \sqrt{25}$

$v = 5 m / s$

Answer 2

Hey mate,

Answer:

5 m / sec

Explanation:

Given :

Initial velocity ( u ) = 0 m / sec

Acceleration ( a ) = 0.5 m/sec^2m/sec

2

Distance ( s ) = 25 m

We have to find final velocity ( v ).

From third equation of motion we have

\large \text{$v^2=u^2+2as$}v

2

=u

2

+2as

where v = final velocity

u = Initial velocity

a = Acceleration

s = Distance

Put the values in equation we get\large \text{$v^2=0^2+2\times25\times0.5$}v2=02 +2×25×0.5\begin{gathered}\large \text{ $v^2=50\times0.5$ }\\\\\\\large \text{$v^2=25$}\\\\\\\large \text{$v=\sqrt{25}$}\\\\\\\end{gathered}

v 2=50×0.5 v 2 =25v= 25

Hope it helps...