Question

a car initially at rest starts moving with a constant acceleration of 0.5 m/s^2 and travels a distance of 25 m find its final velocity and time taken.

Answer 1

Answer:

v^2-u^2=2as

u=0

a=0.5 m/s^2

S=25m

v^2-0^2=2×0.5×25

v^2=25

v=5m/sec

v=u+at

5=0+(0.5×t)

5=0.5t

t=5÷0.5

t=20sec

Answer 2

Answer:

For finding time , we use the second equation of motion .

S = 1/2 at²

25 = 1/2 × 0.5 × t²

50 = 0.5t²

t² = 100

t =√100

 = 10 sec

final velocity can be found using the first equation of motion .

v = u + at

  = 0.5×10

  = 5 m/s

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