Question

A car initially at rest starts moving with a
constant acceleration of 0.5m/s2 and travels
distance of 49 m. Find its final velocity

Answer 1

GiveN :

• Initial velocity (u) = 0 m/s
• Acceleration = 0.5 m/s²
• Distance travelled = 49 m

To FinD :

• Final velocity

SolutioN :

⇒v² - u² = 2as

⇒v² - 0² = 2 * 49 * 0.5

⇒v² = 49*1

⇒v² = 49

⇒v = √49

⇒v = 7 m/s

Answer 2

W.k.t v^2-u^2=2as
u=0
V^2=2x0.5x49
V^2=49
V=7
Therefore final velocity (v) = 7m/s2