a car initially at rest starts moving with a constant acceleration of 0.5m/s and travels a distance of 25m. find its initial velocity and time taken???
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✯Question:
- A car initially at rest starts moving with a constant acceleration of 0.5m/s and travels a distance of 25m. Find it's final velocity and time taken?
✯Given:
- Initial velocity (u) = 0m/s
- Acceleration (a) = 0/5m/s²
- Distance (S) = 25m
✯To find:
- final velocity (v)
- Time taken (t)
✯Solution:
- v² = u² + 2as
- v² = 0² + 2(0.5) × 25
- v² = 25
- v = √25
- Final velocity = 5m/s
✵Final velocity is 5m/s
- v = u + at
- 5 = 0 + 0.5t
- 0.5t = 5
- t = 5÷0.5
- t = 10s
✵Time taken is 10s
Answered by
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Answer:
✯Question:
A car initially at rest starts moving with a constant acceleration of 0.5m/s and travels a distance of 25m. Find it's final velocity and time taken?
✯Given:
Initial velocity (u) = 0m/s
Acceleration (a) = 0/5m/s²
Distance (S) = 25m
✯To find:
final velocity (v)
Time taken (t)
✯Solution:
v² = u² + 2as
v² = 0² + 2(0.5) × 25
v² = 25
v = √25
Final velocity = 5m/s
✵Final velocity is 5m/s
v = u + at
5 = 0 + 0.5t
0.5t = 5
t = 5÷0.5
t = 10s
✵Time taken is 10s
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