a car initially at rest starts moving with a constant accelreration of 0.5m/s and travels a distance of 25m. find final velocity and time taken
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Answered by
34
✯Question✯
- A car initially at rest starts moving with a constant acceleration of 0.5m/s and travels a distance of 25m. Find the velocity and time taken?
✬Given✬
- Initial velocity (u) = 0m/s
- Acceleration (a) = 0.5m/s
- Distance travelled (S) = 25m
☆To find☆
- Final velocity (v)
- Time taken (t)
✮Solution✮
- From equation of motion:
- v² = u² + 2as
- v² = (0)² + 2(0.5)(25)
- v² = 25
- v = √25
- v = 5m/s
➺Final Velocity (v) = 5m/s
- From equation of motion:
- v = u + at
- 5 = 0 + 0.5(t)
- t = 5 ÷ 0.5
- t = 10s
➺Time taken (t) = 10s
Answered by
7
Answer:
Explanation:
u= 0
a= 0.5 m/s
s= 25m
v=? t=?
- = 2as
= 2as +
= 2as + 0
= 2* 0.5 * 25
= 25
v= 5m/s
t=
t= 5-0/ 0.5
t= 5/0.5
t= 10s
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