A car initially at rest starts moving with a constant acceleration of 0.5ms^-2 and travels a distance 25 cm .calculate its final velocity and time taken.
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Explanation:
Given Initial velocity u = 0
Acceleration a = 0.5ms -2
Distance travelled S = 25m
i)Final velocity
From equation of motion v² 02+2 x 0.5 x 25 = u² + 2aS
v² = 25
v = √25
\rm \fbox{\therefore \: final \: velocity \: v\: = 5 ms{}^{-1} }
ii) Time taken
From equation of motion v = u + at
50+ 0.5 xt
0.5 x t = 5
t =
5
0.5
V90
\therefore time taken = 10s
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