Question

A car initially at rest starts moving with an acceleration of 4 ms-2. The time in which it picks up​

Answer 1

Explanation:

Given,

initial velocity(u)=0 m/s

acceleration(a)=4m/s^2

time(t)=?

We know that,

v = u + at

=0+ 4×t

=4t eqn 1

Again,

a=v-u/t

t=v-u/a

=4t-0/4

=4t/4

=t